64x^2=18

Solution for 64x^2=18 equation:

64x^2=18

We move all terms to the left:

64x^2-(18)=0

a = 64; b = 0; c = -18;
Δ = b2-4ac
Δ = 02-4·64·(-18)
Δ = 4608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{4608}=\sqrt{2304*2}=\sqrt{2304}*\sqrt{2}=48\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48\sqrt{2}}{2*64}=\frac{0-48\sqrt{2}}{128}
=-\frac{48\sqrt{2}}{128}
=-\frac{3\sqrt{2}}{8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48\sqrt{2}}{2*64}=\frac{0+48\sqrt{2}}{128}
=\frac{48\sqrt{2}}{128}
=\frac{3\sqrt{2}}{8}
$